Simple Linear Program

Purpose is to know how it looks solving linear programs using libraries and solvers.

Reference : https://pythonhosted.org/PuLP/CaseStudies/a_blending_problem.html

 


\* Minimize food cost *\
Minimize
Total_Cost: 0.008 Beef_percentage + 0.013 chicken_percentag
Subject To
Fat_Constraint: 0.1 Beef_percentage + 0.08 chicken_percentag >= 6
Fiber_Constrint: 0.005 Beef_percentage + 0.001 chicken_percentag <= 2
Protine_Constraint: 0.2 Beef_percentage + 0.1 chicken_percentag >= 8
Salt_constraint: 0.005 Beef_percentage + 0.002 chicken_percentag <= 0.4
Total_Sum: Beef_percentage + chicken_percentag = 100
End


"""
THis is taken from https://pythonhosted.org/PuLP/CaseStudies/a_blending_problem.html
"""
from pulp import *
problem = LpProblem("Minimize food cost", LpMinimize)
x1 = LpVariable("chicken_percentag", lowBound=0)
x2 = LpVariable("Beef_percentage", lowBound=0, upBound=None)
problem += 0.013*x1 + 0.008*x2, "Total Cost"
problem += x1 + x2 == 100, "Total Sum"
problem += 0.1*x1 + 0.2*x2 >=8, "Protine Constraint"
problem += 0.08*x1 + 0.1*x2 >=6, "Fat Constraint"
problem += 0.001*x1 + 0.005*x2 <=2, "Fiber Constrint"
problem += 0.002*x1 + 0.005*x2 <=0.4, "Salt constraint"
problem.writeLP("minimize_food_cost.lp")
problem.solve()
print "Solution found was :", LpStatus[problem.status]
print "Here is the proportional of chick and beef that should be used"
for v in problem.variables():
print "\t",v.name, " : ", v.varValue
print "Cost will be : ", value(problem.objective)

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pulp_LP.py

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Solution found was : Optimal
Here is the proportional of chick and beef that should be used
Beef_percentage : 66.666667
chicken_percentag : 33.333333
Cost will be : 0.966666665

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std_output.txt

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